Practising simple interest
Simple interest is part of the lower secondary curriculum and appears in tests, final exams and commercial training. The six exercises in this article cover all typical questions: interest, daily interest, principal, rate, time and starting capital. All exercises use the German method with 360 days per year and 30 days per month, as in most German textbooks.
Try to solve each exercise yourself first. You can then check your answer against the solution or in the interest calculator, which shows the worked solution step by step.
The formulas at a glance
- Interest: I = P · r · t / 100
- Principal: P = I · 100 / (r · t)
- Rate: r = I · 100 / (P · t)
- Time: t = I · 100 / (P · r)
Time t is always in years. Divide months by 12 and days by 360.
Exercise 1: interest for months
Ms Kaya invests €4,500 for 8 months at 3.5%. How much interest does she receive?
Solution: t = 8 / 12. I = 4,500 · 3.5 · 8 / (100 · 12) = €105.
Exercise 2: daily interest with dates
A balance of €7,200 earns 2.5% from 10 March to 25 June. Calculate the interest.
Solution: Interest days under the German method: March to June are 3 full months (90 days), plus 15 days from the 10th to the 25th, 105 days in total. I = 7,200 · 2.5 · 105 / (100 · 360) = €52.50.
Exercise 3: find the principal
What principal earns exactly €84 interest in 150 days at 2.8%?
Solution: P = I · 100 · 360 / (r · days) = 84 · 100 · 360 / (2.8 · 150) = 3,024,000 / 420 = €7,200.
Exercise 4: find the rate
Mr Braun pays €270 interest over 9 months on a €12,000 loan. What is the rate?
Solution: t = 9 / 12 = 0.75. r = 270 · 100 / (12,000 · 0.75) = 27,000 / 9,000 = 3%.
Exercise 5: find the time
For how many days must €6,400 be invested at 3.75% to earn €60 interest?
Solution: t = 60 · 100 / (6,400 · 3.75) = 6,000 / 24,000 = 0.25 years. Times 360 that is 90 days.
Exercise 6: starting capital from the final amount
Including interest, a principal has grown to €5,125 in 200 days at 4.5%. What was the starting principal?
Solution: The final amount is P · (1 + r · t / 100). With t = 200 / 360: 1 + 4.5 · 200 / 36,000 = 1.025. P = 5,125 / 1.025 = €5,000. The interest is therefore €125.
This one is tricky: simply deducting 4.5% from €5,125 is wrong, because the rate refers to the starting principal, not the final amount.
Typical mistakes in tests
- Time not converted: 105 days are used directly as t instead of 105 / 360.
- Interest days miscounted: under the German method every month has 30 days, February included.
- Percent divided twice: if you use r = 0.035, do not divide by 100 again.
- Final amount confused with interest: often only I is asked for, not P + I.
A good test is a plausibility check: if the rate comes out above 20% or the term at several centuries, there is almost always a unit error in the time.
Conclusion
Four formulas solve every simple interest problem. What matters is converting time correctly and rearranging cleanly. The derivation of the formulas is explained in simple interest explained. For percentage problems without a time component, try the percentage calculator.
